SUEERIZE Essay Example | Topics and Well Written Essays - 250 words

SUEERIZE - Essay Example Xavantes have since then, perfectly secured themselves from outside attacks, though the nature is too difficult to cope with. The economic strength of a nation restricts the conservation. Poor countries are not very conscious about environment and generally look for technological advancement and education, food, health and safety. International agencies help poor countries unite their conservation programs with their economy. Organization of the â€Å"debt for nature swap† in 1987 helped Bolivia get $650,000 as debt for 160,000 sq m of forest. These days, the very area serves as a biposphere reserve. There is a complete ecosystem whose central zone is so carefully controlled that interference is not possible. Nonetheless, it is permissible to conduct research in the transition zone. In order to provide the ecosystem with complete security, a buffer zone is added. Such ecosystems in the whole world are above 250 in number.

Analyse using stat Assignment Example | Topics and Well Written Essays - 1500 words

Analyse using stat - Assignment Example Compare and contrast the findings from the histograms and from the tests with level and logarithmic specifications. H0: sample is not distributed normally H1: sample is distributed normally Decision: Probability value is less than 0.05significance level. Therefore we reject the null hypothesis and accept the alternative hypothesis. i.e. price variable is normally distributed Probability value is less than 0.05significance level. Therefore reject the null hypothesis and accept the alternative hypothesis. i.e. log price variable is also normally distributed Thus, the results of histogram and Kolmogorov-Smirnov test are consistent. Variable Description Combined K-S Value 1. dist Weighted distance to 5 employment centers 0.000 2. ldist Logarithm of weighted distance to 5 employment centers 0.016 H0: sample is not distributed normally H1: sample is distributed normally Decision: Probability value is less than 0.05significance level. Therefore reject the null hypothesis and accept the alte rnative hypothesis. i.e. dist variable is normally distributed Probability value is less than 0.05significance level. Therefore reject the null hypothesis and accept the alternative hypothesis. i.e. log-dist variable is also normally distributed Histogram showed the distribution of dist variable as skewed to the left. However Kolmogorov-Smirnov test yields a normal distribution. ... Mean value of rooms in the given sample is 6.28. Accordingly there are 278 houses with number of rooms bellow the average (sample A) and 228 houses with number of rooms above the average (sample B). Hence the total observations in two samples are different. Therefore we have to conduct unpaired two sample t-test. Mean Difference -8918.208 t-statistics -12.3611 P-value H0: diff=0 0.0000 H1: diff 0 1.0000 Decision: Probability value of H0 is less than 0.05 significant level. Therefore reject H0 which states there is no statistically significant difference between the mean price of houses having rooms less than average and more than average. (ii) houses below and above the average value for nox; Average nox value of the given data set is 5.549. There are 292 observations in the above average category while there are 214 observations in the below average category. Therefore unpaired, two-sample t-test with equal variances can be used. Mean Difference 6199.578 t-statistics 7.9261 P-value H0: diff=0 0.0000 H1: diff 0 0.0000 Decision: Probability value of H0 is less than 0.05 significant level. Therefore we reject the null hypothesis which states mean price of houses which are situated in lower nitrous oxide levels are not statistically different from those houses situated in higher nitrous oxide areas. (iii) Houses below and above the average value for crime. Average number of crimes committed per capita is 3.611in the given data set. Accordingly there are 128 and 378 numbers of observations in the above and below average categories respectively. Therefore, unpaired, two-sample t-test with equal variances can be used. Mean Difference 8471.173 t-statistics 9.8062 P-value H0: